54p^2-294=0

Solution for 54p^2-294=0 equation:

54p^2-294=0

a = 54; b = 0; c = -294;
Δ = b2-4ac
Δ = 02-4·54·(-294)
Δ = 63504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{63504}=252$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-252}{2*54}=\frac{-252}{108}
=-2+1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+252}{2*54}=\frac{252}{108}
=2+1/3
$